WebbThe perimeter of square S is 40. Square T is inscribed in square S. What is the least possible area of square T? Answer choices are 45, 48, 49, 50, or 52. I can't tell if this is a really obvious question that I'm just not understanding or if there's some trick to it that I'm missing. Can someone show me how to go about this? WebbThe perimeter of square S is 40. Square T is inscribed in Square S. What is the least possible area of square T? If someone could upload a picture explaining the situation and what inscribed actually means. If it's just in it then shouldn't it be something super small like 1 or less? (it's not)
The perimeter of square S is 40. Square T is inscribed in square S
WebbCorrect answer: Quantity A is greater. Explanation: The diagonal of a square creates a 45-45-90 triangle; therefore, considering x as the value for the sides of the square in A, set up the ratio: 1/√2 = x/12 → x = 12/√2. Simplify the square root out of the denominator: x … WebbPerimeter of a square calculator online - easily calculate the perimeter of any square, given the length of its side. Supports many imperial and metric units: mm, cm, meters, km, inches, feet, yards, miles, and more. Perimeter of a square formula. bargain hunter barb
Minimum area of Inscribed Square - Mathematics Stack Exchange
WebbSince we're given the perimeter of square T, we can find its area by using the formula which relates the area A of a square to the square's perimeter P as follows: A = P²/16 Since P = 40, then we can substitute into the above formula in order to find area A for square T as follows: A = 40²/16 = 1600/16 = 100 square units is the area of square T. WebbIf the perimeter of a square is 40 cm, then find the length of its side. A 5 cm B 10 cm C 160 cm D 80 cm Solution The correct option is B 10 cm Given: Perimeter of the square = 40 cm Perimeter of a square = 4×Side ⇒ 4×Side =40 cm ⇒ Side =10 cm ∴ If the perimeter of a square is 40 cm, then the length of its side will be 10 cm. Suggest Corrections 16 Webb24 feb. 2024 · Inscribed Square. The perimeter of square S is 40. Square T is inscribed in square S. What is the least possible area of square T? The answer choices are 45, 48, 49, 50, 52. The answer is 50. I don't see why it can't be 45 so that each side of Square T has length 45^(1/2). Please help. Thanks, bargain hunter aitkin mn